计算出的物体 x 和 y 坐标看起来合理。初始左第六连杆位置约为 (-0.3, -0.352, 0.9215) m,左侧横杆大约在 (-0.36, -0.19) m,接近当前指尖 y 坐标 -0.195米。红椒大约在 (-0.42, -0.09) m,比指尖超出约 0.1米。它似乎出现在左腕部图像中像素 (140, 350) 附近,不过我应当检查估计点 (-0.421, -0.0815, 0.79) m 投影到该相机中的位置。大木制玩具似乎出现在腕部图像右边缘附近,大约在像素 (550, 420)。
篮子中心可能位于 x = -0.3、0 和 0.3米,y 约为 0.10米。假设地面高度为 z = 0.75米,逆投影得到 y = 0.098米,外侧篮子的 x 坐标约为 ±0.328米。因此它们的实际中心可能位于 x = ±0.32米和 y = 0.10米。篮子看起来大约为 0.26 × 0.20米。我仍需要确定桌面高度:它可能是 0.72米,不过在这些环境中 0.74 或 0.75米也很常见。初始第六连杆高度 0.9215米将比 0.75米的桌面高约 0.17米。手指当前处于同一高度,并且看起来靠近物体但没有接触它们。红椒中心在 z = 0.79米、半径 0.04米,也支持 0.75米桌面高度的估计。
篮子底部可能在 z = 0.762米,其边缘在 0.86米。我可以通过匹配可见宽度来细化这一点。在高机位相机图像中,白色篮子底部可能跨越像素 x = 145–244,前上边缘在 y = 194,后上边缘在 y = 141,整体宽度大致跨越 x = 139–252。假设边缘高度为 0.85米,可能意味着世界宽度约为 0.25米。中心位于 x = -0.3、0 和 0.3米以及 y = 0.1米仍然合理。将白色中心在 z = 0.8米处投影是否会得到 u = 182?而在该高度下从 u = 192 进行逆计算反而得到 x = -0.298米,这与 -0.3米非常吻合;蓝色中心匹配零,红色篮子给出 x = 0.303米。这可能表明中心位于这些 x 坐标、y 约为 0.05米,且地面高度为 0.8米。
然而,如果桌面在 0.75米且地面在 0.755米,图像 y = 177 将对应世界 y 约为 0.089米。我选择的像素 (192, 177) 只是一个估计值,可能指示地面或篮子的前部。内部四边形的后边缘大约在图像 y = 142,前边缘大约在 y = 192,地面中心接近 y = 175。地面高度 0.76米给出世界 y 约为 0.089米,因此篮子中心 y 接近 0.09米是合理的。诸如 (-0.32, 0.1) m 的位置可能是合理的估计。我现在可以根据观测来细化导航,而不是依赖精确的篮子坐标。
当前姿态是绕 z 轴旋转 90 度,手指沿世界 +Y 方向水平延伸。对于自上而下的抓取,我需要局部 +X 指向世界 -Z,局部 Y 提供适当的闭合方向。可能的向下四元数包括 [0.5, 0.5, 0.5, 0.5] 或 [0.5, -0.5, 0.5, -0.5],但我应当推导姿态并保持可达性,而不是假设其中一个。我可以使用科学计算库来检查它。
初始旋转是 (90°),因此局部 x 指向世界 +y。我能否通过绕世界 x 轴旋转来获得向下姿态?如果我选择局部 x = [0, 0, -1] 和局部 y = [1, 0, 0],它们的叉积给出局部 z = [0, -1, 0]。以这些局部轴为列的旋转矩阵是 [[0, 1, 0], [0, 0, -1], [-1, 0, 0]]。我暂时将其与四元数 [0.5, -0.5, 0.5, 0.5] 关联,但科学计算库可以检查这一点。或者,局部 x 沿世界 -z 且局部 y 沿世界 -x 将给出局部 z 沿 +y,矩阵为 [[0, -1, 0], [0, 0, 1], [-1, 0, 0]],也许四元数为 [0.5, 0.5, 0.5, -0.5]。这些选择仍然需要可达性预检查。
我最初认为通常的自上而下四元数可能是 [0.5, 0.5, 0.5, 0.5],由 [0.707, 0, 0, 0.707] 绕局部 y 轴旋转 90 度得到。通过 (90°)(90°) 计算,局部 x 变为世界 -z,局部 y 变为世界 -x,局部 z 变为世界 +y。四元数乘积给出 w = 0.707 × 0.707 = 0.5,分量 x = -0.5、y = 0.5、z = 0.5,因此我得到 [0.5, -0.5, 0.5, 0.5]。这沿世界 -x 方向闭合,对于沿 x 方向宽度较小的物体来说看起来合适。
在自上而下的姿态下,手指从第六连杆向下延伸 0.1576米。要接触中心在 z = 0.79米的物体,第六连杆是否需要位于 z = 0.93米左右?实际接触可能发生在手指的中间位置,而不是在最远的指尖处。相关的手指长度或第六连杆到接触点的距离可能约为 0.12米,这表明第六连杆位于物体高度加上 0.12–0.14米,即大约 0.91–0.94米。初始水平手指位于 z = 0.9215米,比 0.79米的物体高约 0.13米。向下的第六连杆高度约为 0.93米将使指尖位于 z = 0.772米附近,低于物体中心但接近它。对于中心在 0.80米的辣椒,这可能充分包住物体。
扁平横杆更困难。对于 z = 0.765米的横杆,第六连杆高度 0.88米将使指尖位于 0.722米左右,低于假设的 0.75米桌面。最远的前伸范围包括尖指尖,而接触区域可能更接近局部 x = 0.10米。我应当检查几何形状。手指在从第六连杆到指尖的 0.1576米距离上看起来呈三角形,并且在当前水平姿态下它们的指尖似乎处于同一高度。如果横杆顶部在 z = 0.77米,我希望指尖位于其中心附近 0.765米处或略低于它,而不向下延伸到 0.722米并与桌子碰撞。
对于扁平横杆,水平接近或 45 度倾斜抓取可能效果更好。另一种可能性是自上而下的第六连杆在 0.91米,使指尖位于 0.752米,大约在桌面水平,接触点沿手指更高处接近 z = 0.78米。但中间接触区域,大约在 z = 0.79–0.85米,对于横杆来说是否太高?垫片可能占据指尖附近约 0.07米,或者内表面可能沿大部分锥形手指延伸。我还不知道。如果抓取接触点在局部 x = 0.12米,一个中心在 z = 0.76米、厚度 0.02米的物体将表明第六连杆在 0.89米,这又会使指尖位于 0.732米并造成桌子碰撞。保持手指在 z = 0.79米水平、沿 +Y 接近并沿 x 方向闭合,可以实现侧向抓取,前提是物体正确定位在手指之间。因此初始姿态可能适合横杆,而自上而下似乎更适合玩具和辣椒。
大约 45 度的向下-向前姿态将减少手指的垂直延伸,同时保持可达性。典型的自上而下目标可能使用 [0.5, -0.5, 0.5, 0.5],对于辣椒和玩具第六连杆在 z = 0.95米左右,对于横杆在 0.92米左右,但我应当从几何形状进行推理。对于 0.77米的横杆和局部 x = 0.12米处的接触点,第六连杆在 0.89米使该接触点位于横杆处,而手指额外的 0.0376米延伸到其下方,指尖在 0.732米。即使手指有斜角,它们的最远延伸仍然是 0.1576米。因此自上而下的横杆抓取可能需要非常接近指尖的接触:第六连杆在 0.9276米使指尖位于 0.77米。第六连杆在 0.925米给出指尖高度约为 0.767米,比假设的桌子高约 0.017米。
使用第六连杆大约高于物体中心 0.15米,对于中心在 0.79米的辣椒将给出 0.94米,指尖接近 0.782米;对于中心在 0.80米的木制玩具则给出 0.95米。将夹爪居中可能允许指尖抓取,尽管尖指尖提供的接触面积有限。将第六连杆降低到物体中心加 0.12米对于较高的物体可能更稳健,但对于较低的物体有接触桌子的风险。对于高度约 0.05米的辣椒,第六连杆在 0.92米使指尖接近 0.762米,比物体中心 0.79米低约 0.028米,但仍高于 0.75米的桌面。对于横杆,第六连杆在 0.915米使指尖接近 0.757米,大约在横杆中间高度 0.762米附近。因此一个暂定规则是:对于横杆,第六连杆位于桌面高度加 0.165米,即 0.915米。对于中心在 0.79米、高度约 0.08米且位于 0.75米桌面上的物体,第六连杆在 0.925米将使指尖接近 0.767米。
一旦手臂更近,我应当使用腕部相机细化物体位置。从左侧 (-0.3, -0.352, 0.9215) m 和右侧 (0.3, -0.352, 0.9215) m 出发,向大约 (-0.41, -0.09, 0.79) m 的红椒移动将需要约 0.29米的距离,超过 0.25米的目标界限。将右臂向 (0.40, -0.11, 0.77) m 的右侧横杆移动约为 0.27米,因此两者都需要中间目标。
我考虑过从大约 (-0.17, -0.13) m 的大木制玩具和大约 (0.4, -0.11) m 的右侧横杆开始,或者从大玩具和摇摇马开始。两个玩具都会去白色篮子,并且在同时放置时可能相互干扰。同样,同时抓取红椒和黄椒会使两条手臂都朝向蓝色篮子。从左手红椒和右手右侧巧克力棒开始,会给出不同的目的地和更清晰的路径。之后,当左臂将左侧横杆移到红色篮子而右臂将黄椒移到蓝色篮子时,可能需要交错或顺序运动,因为它们的路径可能交叉。大玩具和马也共享白色篮子,因此它们的放置应当分开,然后根据需要处理小玩具。七个物体每个大约十个动作,将约为 70 次调用和 700 个控制步,在 1100 步预算之内。我短暂地想过是否只有六个物体,但左侧那个红白相间的小物体确实看起来是另一根巧克力棒。
一个有用的第一对是:左臂将红椒放入蓝色篮子,右臂将紫色横杆放入红色篮子。左侧物体的路径从 x 约 -0.4米到零,而右侧横杆从 x 约 0.4米移动到 0.3米。篮子目标将使夹爪相距约 0.3米,而手指宽度约为 0.1米,因此这些运动看起来足够分离。我可以同时抓取,然后分别放置,或者使用一个具有不同蓝色和红色篮子目标的动作。第二对可以是:左臂将大木制玩具放入白色篮子,右臂将黄椒放入蓝色篮子。它们的接近路径将从 x = 0 到约 -0.17米,以及从 0.3 到约 0.15米,放置目标分别在 -0.3米和零附近。
最后三个物体需要更多注意。同时将左侧横杆移到红色篮子并将马移到白色篮子会造成大量交叉。我可以先用左臂放置小玩具,同时马保持不动,然后顺序处理左侧横杆和马。或者,左臂可以接近并保持在左侧横杆附近,而右臂将马带到白色篮子,然后右臂可以缩回其侧面,之后左臂将横杆放入红色篮子。小玩具可以随后处理。让右臂从 x 约 -0.36米处取回左侧横杆也会穿过左臂的工作区域,而交换哪条手臂处理马并不能消除交叉。让空闲手臂处于其安全初始姿态进行完全顺序工作将更简单且风险更低,而且预算似乎足够。由于在安全时鼓励并行工作,我将使用前两对,并顺序处理剩余物体,验证稳定的抓取和放置。
对于第一对,我可以在仍在空旷空间时将两个张开的夹爪旋转到自上而下,也许还稍微向前移动。初始左手指在 z 约 0.92米处跨越 y 约 -0.35 到 -0.195米。左侧横杆大约在 x = -0.36米、y = -0.19米、z = 0.77米,低约 0.15米。在初始第六连杆位置向下旋转将使指尖在 y = -0.352米处朝向 z = 0.764米,位于横杆后方而不是直接在其上方。右侧同样看起来在 y = -0.352米以下没有物体。
完整的 1.57弧度旋转超过了 1.0弧度的目标姿态限制,即使我只请求三个控制步。我需要绕局部 y 轴进行 45 度的中间旋转。对于 (90°)(45°),中间四元数可能是 [0.6533, -0.2706, 0.6533, 0.2706];我应当计算它。其姿态距离将约为 0.785弧度,在界限之内。我可以将该中间旋转与向物体移动(高度约 0.96米)结合起来。作为间隙检查,当第六连杆在 y = -0.26米和 z = 0.95米时,倾斜的手指将到达大约 y = -0.1485米和 z = 0.8385米,高于 y = -0.19米和 z = 0.77米的左侧横杆。右侧横杆情况类似。我可以稍后下降。
一个建议的左目标在辣椒上方,为 (-0.41, -0.10, 0.99) m,最终采用自上而下的姿态。它距当前姿态约 0.29米,因此我可以先使用 (-0.36, -0.23, 0.96) m,距离约 0.147米。右目标 (0.40, -0.12, 0.96) m 距当前姿态约 0.264米,略超过 0.25米限制;中间点 (0.35, -0.23, 0.96) m 距离约 0.14米。我可以使用中间 45 度姿态和这些位置,两个夹爪都张开,也许进行五步,然后完全旋转并继续到物体上方。
在移动之前,我想要更好的定位。高机位相机像素 (122, 228) 是红椒的中心还是其顶部?在 z = 0.82米处逆投影给出大约 x = -0.405米和 y = -0.094米,而先前 z = 0.79米假设下为 x = -0.421米。如果我能在每个相机中识别同一点,标定后的高机位相机和腕部相机可以提供双视图三角测量。绿色茎中心是一个可能的对应点:也许在高机位相机中为像素 (121, 224),在左腕部相机中为 (137, 322)。这些像素估计仍然不确定。准确的对应关系和标定可以精确定位该世界点。我将生成放大的左腕部和右腕部图像,以便检查参考点并估计其坐标。
原文14,034 字
The calculated object x and y coordinates look plausible. The initial left link6 position is approximately (-0.3, -0.352, 0.9215) m, and the left bar is around (-0.36, -0.19) m, close to the current fingertip y coordinate of -0.195 m. The red pepper is around (-0.42, -0.09) m, about 0.1 m beyond the fingertips. It appears near pixel (140, 350) in the left wrist image, though I should check the projection of the estimated point (-0.421, -0.0815, 0.79) m into that camera. The large wooden toy appears near the wrist image’s right edge, around pixel (550, 420).
The basket centers may be at x = -0.3, 0, and 0.3 m, with y around 0.10 m. Assuming a floor height of z = 0.75 m, the inverse projections give y = 0.098 m and outer basket x coordinates around ±0.328 m. Their actual centers could therefore be at x = ±0.32 m and y = 0.10 m. The baskets look approximately 0.26 by 0.20 m. I still need to establish the tabletop height: it could be 0.72 m, although 0.74 or 0.75 m is common in these environments. The initial link6 height of 0.9215 m would be about 0.17 m above a 0.75 m tabletop. The fingers are currently at that same height and appear near the objects without touching them. A red pepper center at z = 0.79 m with radius 0.04 m also supports the 0.75 m tabletop estimate.
The basket floor might be at z = 0.762 m and its rim at 0.86 m. I could refine this by matching the visible width. In the high-camera image, the white basket floor may span pixels x = 145–244, with the front top edge at y = 194, the back top edge at y = 141, and the overall width spanning roughly x = 139–252. Assuming a rim height of 0.85 m might imply a world width around 0.25 m. Centers at x = -0.3, 0, and 0.3 m and y = 0.1 m remain plausible. Would projecting the white center at z = 0.8 m give u = 182? The inverse calculation from u = 192 at that height instead gave x = -0.298 m, which closely matches -0.3 m; the blue center matches zero, and the red basket gives x = 0.303 m. That could suggest centers at those x coordinates, y around 0.05 m, and a floor height of 0.8 m.
However, if the tabletop is at 0.75 m and the floor is at 0.755 m, image y = 177 would correspond to world y around 0.089 m. My selected pixel (192, 177) was only an estimate and might indicate the floor or the front of the basket. The interior quadrilateral has its back rim around image y = 142 and its front rim around y = 192, with the floor center near y = 175. A floor height of 0.76 m gives world y around 0.089 m, so a basket center y near 0.09 m is plausible. Positions such as (-0.32, 0.1) m may be reasonable estimates. I can refine navigation from observations rather than relying on exact basket coordinates now.
The current orientation is a 90-degree rotation about z, with the fingers extending horizontally along world +Y. For a top-down grasp, I need local +X to point along world -Z and local Y to provide an appropriate closing direction. Possible downward quaternions include [0.5, 0.5, 0.5, 0.5] or [0.5, -0.5, 0.5, -0.5], but I should derive the orientation and preserve reachability rather than assume one. I can use SciPy Rotation to check it.
The initial rotation is Rz(90°), so local x points along world +y. Could I obtain the downward orientation by rotating about world x? If I choose local x = [0, 0, -1] and local y = [1, 0, 0], their cross product gives local z = [0, -1, 0]. The rotation matrix, with these local axes as columns, is [[0, 1, 0], [0, 0, -1], [-1, 0, 0]]. I tentatively associate this with quaternion [0.5, -0.5, 0.5, 0.5], but SciPy can check that. Alternatively, local x along world -z and local y along world -x would give local z along +y, with matrix [[0, -1, 0], [0, 0, 1], [-1, 0, 0]] and perhaps quaternion [0.5, 0.5, 0.5, -0.5]. These choices would still need the reachability precheck.
I initially thought the usual top-down quaternion might be [0.5, 0.5, 0.5, 0.5], obtained from [0.707, 0, 0, 0.707] by rotating 90 degrees about local y. Working through Rz(90°)Ry(90°), local x becomes world -z, local y becomes world -x, and local z becomes world +y. The quaternion product gives w = 0.707 × 0.707 = 0.5 and components x = -0.5, y = 0.5, z = 0.5, so I arrive at [0.5, -0.5, 0.5, 0.5]. This closes along world -x, which looks appropriate for objects with a small width along x.
With a top-down orientation, the fingers extend 0.1576 m below link6. To contact an object centered at z = 0.79 m, would link6 need to be around z = 0.93 m? The actual contact may occur partway along the fingers rather than at their farthest tips. The relevant finger length or link6-to-contact distance might be around 0.12 m, suggesting link6 at the object height plus 0.12–0.14 m, or around 0.91–0.94 m. The initial horizontal fingers are at z = 0.9215 m, about 0.13 m above objects at 0.79 m. A downward link6 height around 0.93 m would put the tips near z = 0.772 m, below the object center but close to it. For a pepper centered at 0.80 m, that may encompass the object adequately.
Flat bars are more difficult. For a bar at z = 0.765 m, a link6 height of 0.88 m would put the tips around 0.722 m, below an assumed tabletop at 0.75 m. The farthest forward extent includes the pointed tips, while the contact region might be closer to local x = 0.10 m. I should inspect the geometry. The fingers appear triangular over the 0.1576 m distance from link6 to their tips, and their tips appear to share the same height in the current horizontal pose. If the bar top is at z = 0.77 m, I want the tips at or slightly below its center near 0.765 m, without extending down to 0.722 m and colliding with the table.
A horizontal approach or a 45-degree tilted grasp might work better for a flat bar. Another possibility is top-down link6 at 0.91 m, giving tips at 0.752 m, approximately table level, with contact higher along the fingers near z = 0.78 m. But would the middle contact region, around z = 0.79–0.85 m, be too high for the bar? The pads might occupy roughly 0.07 m near the tips, or the inner surfaces might extend along most of the tapered fingers. I do not yet know. If the grasp contact is at local x = 0.12 m, a 0.02 m thick object centered at z = 0.76 m would suggest link6 at 0.89 m, again putting the tips at 0.732 m and creating a table collision. Keeping the fingers horizontal at z = 0.79 m, approaching along +Y, and closing across x could allow a side grasp, provided the object is properly positioned between the fingers. The initial orientation may therefore be suitable for bars, while top-down seems better for toys and peppers.
A roughly 45-degree downward-forward orientation would reduce the vertical finger reach while retaining access. Typical top-down targets might use [0.5, -0.5, 0.5, 0.5], with link6 around z = 0.95 m for peppers and toys and 0.92 m for bars, but I should reason from the geometry. For a bar at 0.77 m and contact at local x = 0.12 m, link6 at 0.89 m puts that contact at the bar while the extra 0.0376 m of finger reaches below it, with the tip at 0.732 m. Even if the fingers are beveled, their farthest extent is still 0.1576 m. A top-down bar grasp may therefore need contact very near the tips: link6 at 0.9276 m puts the tips at 0.77 m. Link6 at 0.925 m gives a tip height around 0.767 m, about 0.017 m above the assumed table.
Using link6 approximately 0.15 m above the object center would give 0.94 m for a pepper centered at 0.79 m, with tips near 0.782 m, and 0.95 m for a wooden toy centered at 0.80 m. Centering the gripper could permit a fingertip grasp, although pointed tips offer limited contact area. Lowering link6 to the object center plus 0.12 m could be more robust for taller objects, but risks table contact for low ones. For peppers about 0.05 m high, link6 at 0.92 m gives tips near 0.762 m, about 0.028 m below an object center at 0.79 m but still above the 0.75 m tabletop. For bars, link6 at 0.915 m gives tips near 0.757 m, around a bar’s middle height of 0.762 m. A tentative rule is therefore link6 at tabletop height plus 0.165 m, or 0.915 m, for bars. For objects centered at 0.79 m and about 0.08 m high on the 0.75 m table, link6 at 0.925 m would put the tips near 0.767 m.
I should refine object positions with the wrist cameras once the arms are nearer. Starting from left (-0.3, -0.352, 0.9215) m and right (0.3, -0.352, 0.9215) m, moving toward the red pepper at approximately (-0.41, -0.09, 0.79) m would require a distance around 0.29 m, exceeding the 0.25 m target bound. Moving the right arm toward the right bar at (0.40, -0.11, 0.77) m is around 0.27 m, so both need intermediate targets.
I considered starting with the large wooden toy near (-0.17, -0.13) m and the right bar near (0.4, -0.11) m, or with the large toy and the rocking horse. Two toys would both go to the white basket and could interfere during simultaneous placement. Likewise, picking the red and yellow peppers together would send both arms toward the blue basket. Starting with the left arm’s red pepper and the right arm’s right-hand chocolate bar gives separate destinations and clearer paths. Later, moving the left bar to the red basket while the right arm moves the yellow pepper to the blue basket might require staggered or sequential motions because their paths could cross. The large toy and horse also share the white basket, so their placements should be separated, followed by the small toy as needed. Seven objects at roughly ten actions each would be about 70 calls and 700 control steps, within the 1100-step budget. I briefly wondered whether there were only six objects, but the small red-and-white object on the left does appear to be another chocolate bar.
A useful first pair is the red pepper to the blue basket with the left arm and the purple bar to the red basket with the right. The left object’s path runs from x around -0.4 m to zero, while the right bar moves from x around 0.4 m to 0.3 m. The basket targets would leave the grippers about 0.3 m apart, compared with a finger width around 0.1 m, so these motions appear sufficiently separated. I can pick together and either place separately or use one action with distinct blue and red basket targets. The second pair could be the large wooden toy to the white basket with the left arm and the yellow pepper to the blue basket with the right. Their approach paths would run from x = 0 to about -0.17 m and from 0.3 to about 0.15 m, with placement targets near -0.3 m and zero.
The last three objects need more care. Moving the left bar to the red basket and the horse to the white basket simultaneously would cause substantial crossing. I could first place the small toy with the left arm while the horse remains untouched, then handle the left bar and horse sequentially. Alternatively, the left arm could approach and hold near the left bar while the right arm takes the horse to the white basket, then the right arm could retract to its side before the left arm places the bar in the red basket. The small toy could follow. Having the right arm retrieve the left bar from x around -0.36 m would also cross the left arm’s working area, and swapping which arm handles the horse does not eliminate the crossing. Fully sequential work with the idle arm at its safe initial pose would be simpler and lower risk, and the budget seems sufficient. Since parallel work is encouraged when safe, I will use the first two pairs and handle the remaining objects sequentially, verifying stable grasps and placements.
For the first pair, I could rotate both open grippers toward top-down while still in clear space, perhaps also shifting forward slightly. The initial left fingers span y around -0.35 to -0.195 m at z around 0.92 m. The left bar is at approximately x = -0.36 m, y = -0.19 m, z = 0.77 m, about 0.15 m lower. Rotating downward at the initial link6 position would take the tips toward z = 0.764 m at y = -0.352 m, behind the bar rather than directly over it. The right side likewise appears to have no object beneath y = -0.352 m.
A full 1.57 rad rotation exceeds the 1.0 rad target orientation limit, even if I request only three control steps. I need a 45-degree intermediate rotation about local y. For Rz(90°)Ry(45°), the intermediate quaternion might be [0.6533, -0.2706, 0.6533, 0.2706]; I should calculate it. Its orientation distance would be about 0.785 rad, within the bound. I could combine that intermediate rotation with a move toward the objects at a height around 0.96 m. As a clearance check, with link6 at y = -0.26 m and z = 0.95 m, tilted fingers would reach approximately y = -0.1485 m and z = 0.8385 m, above the left bar at y = -0.19 m and z = 0.77 m. The right bar has a similar situation. I can descend later.
A proposed left target above the pepper is (-0.41, -0.10, 0.99) m, eventually with the top-down orientation. Its distance from the current pose is around 0.29 m, so I could first use (-0.36, -0.23, 0.96) m, about 0.147 m away. The right target (0.40, -0.12, 0.96) m is around 0.264 m from the current pose, slightly over the 0.25 m limit; an intermediate point (0.35, -0.23, 0.96) m is around 0.14 m away. I could use the intermediate 45-degree orientation and these positions with both grippers open, perhaps for five steps, then rotate fully and continue above the objects.
Before moving, I want better localization. Is high-camera pixel (122, 228) the red pepper’s center or its top? Inverting at z = 0.82 m gives approximately x = -0.405 m and y = -0.094 m, compared with x = -0.421 m under the earlier z = 0.79 m assumption. The calibrated high and wrist cameras could provide two-view triangulation if I identify the same point in each. The green stem center is a possible correspondence: perhaps pixel (121, 224) in the high camera and (137, 322) in the left wrist camera. Those pixel estimates remain uncertain. Accurate correspondences and calibration could locate that world point precisely. I will generate enlarged left and right wrist images so I can inspect the reference points and estimate their coordinates.