物体已被释放。在高机位相机视图中,手表可见于白色篮子的右前方附近,蓝色篮子内部可见小汽车的青绿色部分。腕部视图显示手表躺在白色篮子的底部,小汽车在蓝色篮子的底部。我应当将夹爪撤回至空旷区域,并确认两个物体保持稳定。
还剩四个物体:中央手表、中央小汽车、狮子和马。剩余 937 个控制步;前两个物体用了 163 步,主要因为旋转。我可以利用学到的关于向下抓取和向前放置的经验,或许可以同时运动,并在间隙允许时使用 15 步的动作。左侧第六连杆靠近白色篮子,位于 [−0.317, −0.078, 0.913] m,姿态别扭;右侧靠近蓝色篮子,位于 [−0.003, −0.079, 0.897] m。在当前高机位视图中,狮子出现在像素 (158, 245) 附近,马在 (199, 247) 附近,中央小汽车在 (256, 265) 附近,中央手表在 (352, 241) 附近。
我需要选择一种能限制路径交叉和困难伸展的分配方案。用左臂抓取狮子、右臂抓取中央手表会将它们送往相反的篮子,运输路径会相交。用左臂抓取中央小汽车、右臂抓取中央手表也会在蓝色篮子附近产生潜在冲突。另一种选择是用不同的臂分别抓取狮子和马,并依次将它们放入红色篮子,然后再处理中央小汽车和手表。我可以让一只臂沿交叉路线移动,同时另一只臂保持其测量姿态或为下一个物体做准备。
最简单的分配似乎是将两个木制玩具分配给左臂,将中央小汽车和手表分配给右臂。这样左臂有两次交叉到红色篮子,右臂有一次交叉到白色篮子。另一种方案是左臂负责中央小汽车和狮子,右臂负责中央手表和马。每种方案各有一次交叉放置,但右臂还需要交叉到左侧去抓取马。在左臂抓取相邻的狮子时抓取马可能会造成干扰。我可以改为一起抓取中央小汽车和手表:我初步估计它们的 X 间距约为 0.13米,小汽车在 X ≈ −0.13米,手表在 X ≈ +0.065米。它们的接近似乎是可行的,但右臂从 X ≈ +0.07米到 −0.315米的路线会经过蓝色篮子上方,而左臂正在那里放置小汽车。先放置小汽车而让右臂等待可以避免该冲突,但这种分配更复杂。
我可以将较简单的分配组织为两个阶段。首先,左臂抓取狮子,右臂抓取中央小汽车。狮子从 X ≈ −0.34米到红色篮子 X ≈ +0.315米的路线与小汽车从 X ≈ −0.13米到蓝色篮子 X = 0米的路线在附近交叉。我可以将左臂保持得更高,或许在 Z = 1.1米,右臂更低,但伸展约束使高度分离不确定。狮子靠近 Y = −0.15米的前方路线可能有帮助,尽管两臂仍可能在 X = 0米和 Y ≈ −0.08米附近相交。更安全的顺序是左臂将狮子举高,同时右臂放置小汽车,然后在左臂交叉到红色篮子之前将右臂移向中央手表。一旦右臂离开蓝色篮子,这些准备和运输动作或许可以同时进行。
在第二阶段,左臂将马送到红色篮子,右臂将中央手表送到白色篮子。它们的路径再次交叉,因此我可以先放置手表,同时左臂保持马,然后在右臂撤回后移动马。相反的顺序也是可能的。保持一只臂静止将需要更多调用,但剩余预算充足。
伸展仍然是一个问题。另一种分配是将中央手表放在左臂以放置到白色篮子,将其他三个物体全部放在右臂以放置到蓝色和红色篮子。左臂只需交叉到 X ≈ +0.065米处抓取手表;右臂将交叉到 X ≈ −0.13米处抓取中央小汽车,以及更左侧的两个木制玩具。它们的中央接近需要按顺序进行。我也可以使用一只臂处理所有剩余物体以避免臂与臂之间的交叉;大约 900 步似乎足够。右臂已到达中央的蓝色和白色篮子,但到达 X = −0.35米、Y = −0.1米附近的左侧物体可能需要从其基座延伸约 0.6米。左臂以向下姿态到达 X ≈ +0.315米、Y ≈ −0.08米处的红色篮子也未经证实。它已到达 X ≈ −0.315米处的白色篮子,右臂已到达蓝色篮子,但这两个结果都不能证明更困难的横向伸展。
也许这些任务允许臂以向前水平姿态到达整个桌面。从 X = −0.3米附近的左基座出发,放置到 X ≈ +0.315米处的红色篮子需要横向约 0.6米,可能接近 0.6米的最大值。将木制玩具分配给右臂可以避免该放置伸展,但在 X = −0.35米、Y = −0.1米、Z = 0.93米附近的向下抓取距离 X = +0.3米处的右基座约 0.65米,可能无法到达。交接是另一种可能性,尽管我更愿意避免。将红色篮子移近并在稍后移回是技能建议的备选方案,但不是满足所要求右篮放置的理想方式。我应首先测试合适的放置姿态是否能使左臂伸展成为可能。
基座实际上可能不在 X = ±0.3米。在高机位视图中,左基座似乎位于 X = −0.4米、Y = −0.45米附近,右基座位于 X = +0.4米附近。如果是这样,从左到红色篮子的伸展可能约为 0.8米,在不改变放置几何形状的情况下是不可能的。手指可以提供一些横向延伸。在中间旋转过程中,其方向摆向 +X,增加约 0.05米,而完全水平的初始姿态使它们指向 +Y,不增加 X 方向的伸展。对角 +X/+Y 方向可以横向增加约 0.11米。将手指指向 +X 可以增加约 0.158米:第六连杆在 X = +0.16米处会使指尖接近 X = +0.318米,从 X = −0.3米的基座出发需要约 0.46米。这可能使红色篮子放置变得可行。
因此我应保持放置姿态灵活。从开始,其局部 X 指向环境 +Y,绕环境 Z 轴偏航 −90 度应使手指指向 +X。我初步计算 = (−90°) × 为顺序的 [0.5, −0.5, 0.5, 0.5]:将 [0.707, 0, 0, −0.707] 乘以 [0.707, 0, 0, 0.707] 得到该结果。这类似于之前的向下姿态候选,因此我需要检查其实际的局部 X 方向,而不是假设它指向 +X。我估计从开始的该偏航变化为 90 度,即 1.571弧度,需要一个中间姿态。−45 度偏航也可能提供足够的伸展。相机最终的方向仍需检查,我不需要在抓取之前解决这个问题。
在接下来的抓取之前,我应撤回至空旷空间,或许朝向 Z = 1.03米和 Y = −0.25米。为左臂选择中央手表需要以向下姿态到达 X ≈ +0.065米、Y ≈ −0.1米、Z = 0.93米,从其估计基座横向约 0.38米。这可能是可行的,预检查可以帮助评估。右臂可以改为抓取手表并以手指指向 −X 的方式将其放入白色篮子。对于木制玩具,右臂在 X ≈ −0.34米处抓取狮子将涉及横向约 0.64米,而左臂在 X ≈ +0.315米处放置到红色篮子约为 0.615米。侧向手指可能使任一一条路线可行。将玩具分配给两臂是另一种选择:右臂在 X ≈ −0.25米处抓取马将涉及约 0.55米,而左臂抓取狮子容易,但需要约 0.62米的交叉放置。交接仍然可能,但目前似乎没有必要。
我将首先进行左臂将狮子送到红色篮子、右臂将中央小汽车送到蓝色篮子,然后左臂将马送到红色篮子、右臂将中央手表送到白色篮子。如果即使采用侧向放置,左臂仍无法到达红色篮子,我可以重新考虑右臂交接或移动篮子。我认为计划的方法可能可行,但尚未验证。
两个夹爪都在白色和蓝色篮子上方张开,几乎水平,大约在 Z = 0.91米。我可以向 Z = 1.05米抬起,同时向 Y = −0.18米撤回。我估计左臂位移为 Y 方向 −0.1米和 Z 方向 +0.14米,范数为 0.172米,右臂位移类似,约为 0.17米。我可以在撤回期间保持它们的姿态,但向下抓取将需要旋转。使用当前左四元数 [0.793, 0.008, 0.211, 0.572] 和向下四元数 [0.707, 0, 0.707, 0],我估计点积为 0.56 + 0.149 = 0.709,姿态距离为 1.57弧度,超过 1弧度的限制。对于右四元数 [0.773, −0.005, 0.144, 0.618],我估计为 0.546 + 0.102 = 0.648,距离为 1.73弧度。两者都需要中间旋转。我可以使用中点姿态,或考虑替代的向下四元数 [0, 0.707, 0, −0.707],它沿 Y 方向闭合但使相机朝上。我对该替代方案的点积初步计算为 0.149 − 0.404 = −0.255,绝对值为 0.255,姿态距离为 2.88弧度,因此没有帮助。可能再次需要两到三个旋转阶段,但现在我可以将中间旋转与接近运动结合,因为没有抓取物体。
从前方进行水平抓取是另一种可能性。保持使手指沿 +Y,我可以接近 Y = −0.3米附近并在 Z ≈ 0.78米处抓取,避免向下旋转并简化放置。对于小汽车和木制玩具,第六连杆在 Z ≈ 0.80米处可以让手指跨在物体两侧,同时沿环境 X 方向闭合,因为的局部 Y 指向 −X。沿小汽车 X 方向对齐的长度闭合可能不如沿其宽度闭合合适,但 90 度偏航可以改变闭合方向。直立的手表可以沿其 X 宽度水平接近,狮子或马可以在 Z ≈ 0.82米处跨身体抓取。如果垫片延伸过低,水平手指可能会接触桌面;估计厚度为 0.02米表明 Z = 0.80米可能足够,但我尚未验证。
对于这样的抓取,我会将第六连杆放在物体中心高度,并在 Y 方向位于其后方约 0.15米处,使用指尖几何进行对齐。腕部相机将向前下方看。跨小汽车前后抓取可能仍然稳定。马需要一个合适的狭窄抓取区域,而不是在其底部或头部任意闭合。我估计狮子的 X 宽度为 0.05米,Y 深度为 0.04米,马的 X 宽度为 0.04米,Y 深度可能为 0.08米。中央小汽车可能有一个沿 X 方向的对角长轴,长度约 0.07米,宽度约 0.04米;45 度偏航可能更好地使垫片跨其宽度对齐。尽管如此,向下抓取已经成功,并且是这里更可靠的选择。
剩余 937 步,估计每个物体约 80 步,四个物体总共 320 步,留有充足余量。我将继续使用向下抓取,在适当的地方使用精确的中间值和 15 步运动。我可以在旋转通过从每个测量姿态到向下姿态 55% 处的中间姿态时,移动到下一个目标上方。
狮子的抓取点仍需要立体细化。其圆形身体可能接近像素 (161, 248),头部接近 (149, 241),但我不确定哪部分是哪部分。初始裁剪可能显示它朝左,大鬃毛或头部在右侧。我可以检查高机位相机裁剪图或将腕部移到其上方以获得更清晰的视图;当前左腕部主要显示白色。中央小汽车同样可以从高机位视图估计,并用腕部相机细化。
使用暂定的抓取高度 Z = 0.79米,狮子像素 (157, 247) 可能给出 X ≈ −0.340米。之前,Z = 0.78米处的像素 (158, 246) 给出大约 X = −0.339米、Y = −0.12米;在 Z = 0.79米处我估计 X ≈ −0.332米、Y ≈ −0.125米。Z = 0.79米处的马像素 (199, 247) 可能给出 X ≈ −0.239米、Y ≈ −0.125米。Z = 0.78米处的中央小汽车像素 (256, 264) 可能给出 X ≈ −0.131米、Y ≈ −0.161米。Z = 0.79米处的中央手表像素 (352, 242) 可能给出 X ≈ +0.062米、Y ≈ −0.116米。我将计算所选高度处的坐标。桌子可能在 Z = 0.75米,小汽车中心大约在 Z = 0.775米,狮子身体顶部可能在 Z = 0.79米,抓取中心在 Z = 0.80米。马的身体也可能在 Z = 0.80米。接近时第六连杆高度 Z = 1.04米应允许在其上方观察和对齐。
臂当前在 Y = −0.08米附近,而物体在 Y = −0.12 到 −0.16米附近,因此接近距离不远。狮子大约在 X = −0.33米、Y = −0.125米,中央小汽车在 X = −0.13米、Y = −0.16米。两臂可以并排接近,间隔约 0.2米。它们位于前缘上方,因此我打算在向 Z = 1.05米抬起并朝向下旋转的同时,沿负 Y 方向朝物体移动。在命令运动之前,我将计算从每个当前测量姿态到向下姿态的分数 0.5 和 0.55 处的姿态,以及剩余物体的高机位相机位置估计。
原文13,343 字
The objects have been released. In the high-camera view, the watch is visible near the front-right of the white basket, and a turquoise part of the car is visible inside the blue basket. The wrist views show the watch lying on the white basket’s bottom and the car on the blue basket’s bottom. I should withdraw the grippers into clear space and verify that both objects remain stable.
Four objects remain: the central watch, central car, lion, and horse. There are 937 control steps left; the first two objects took 163 steps, largely because of the rotations. I can use what I learned about downward grasps and forward placement, perhaps making simultaneous motions and using 15-step actions where clearance permits. The left link6 is near the white basket at [−0.317, −0.078, 0.913] m, with an awkward orientation, and the right is near the blue basket at [−0.003, −0.079, 0.897] m. In the current high view, the lion appears near pixel (158, 245), the horse near (199, 247), the central car near (256, 265), and the central watch near (352, 241).
I need to choose an allocation that limits crossing paths and difficult reaches. Picking the lion with the left arm and central watch with the right would send them to opposite baskets, with intersecting transport paths. Picking the central car with the left and central watch with the right also creates a possible conflict near the blue basket. Another option is to pick the lion and horse with separate arms and place both into red sequentially, then handle the central car and watch. I can move one arm at a time through crossing routes while the other holds its measured pose or prepares for its next object.
The simplest allocation seems to be both wooden toys to the left arm and the central car and watch to the right. That gives the left arm two crossings to red and the right one crossing to white. An alternative is the central car and lion for the left arm, and central watch and horse for the right. Each would have one crossing placement, but the right arm would also cross to pick up the horse on the left. Picking the horse while the left arm picks the adjacent lion could cause interference. I could instead pick the central car and watch together: I initially estimate their X separation as about 0.13 m, with the car at X ≈ −0.13 m and the watch at X ≈ +0.065 m. Their approach seems feasible, but the right arm’s route from X ≈ +0.07 m to −0.315 m would pass above blue while the left arm places the car there. Placing the car first while the right arm waits would avoid that conflict, but this allocation is more complicated.
I can organize the simpler allocation into two phases. First, the left arm grasps the lion and the right grasps the central car. The lion’s route from X ≈ −0.34 m to the red basket at X ≈ +0.315 m crosses near the car’s route from X ≈ −0.13 m to blue at X = 0 m. I could hold the left arm higher, perhaps at Z = 1.1 m, and the right lower, but reach constraints make height separation uncertain. A front route for the lion near Y = −0.15 m might help, though the arms could still intersect near X = 0 m and Y ≈ −0.08 m. A safer sequence is to hold the lion high on the left while the right places the car, then move the right arm away toward the central watch before the left crosses to red. Once the right clears blue, those preparation and transport motions might proceed together.
In the second phase, the left arm takes the horse to red and the right takes the central watch to white. Their paths again cross, so I can place the watch first while the left holds the horse, then move the horse after the right retreats. The reverse order is also possible. Holding one arm stationary will require more calls, but the remaining budget is ample.
Reach is still a concern. Another allocation would put the central watch in the left arm for placement into white and all three other objects in the right arm for blue and red. The left arm would cross only to grasp the watch at X ≈ +0.065 m; the right would cross to grasp the central car at X ≈ −0.13 m and both wooden toys farther left. Their central approaches would need to be sequential. I could also use one arm for all remaining objects to avoid arm-to-arm crossings; roughly 900 steps seems enough. The right arm has reached central blue and white, but reaching the left objects near X = −0.35 m, Y = −0.1 m may require about 0.6 m from its base. The left arm’s reach to red at X ≈ +0.315 m, Y ≈ −0.08 m in a downward pose is also unproven. It has reached white at X ≈ −0.315 m, and the right has reached blue, but neither result establishes the harder lateral reach.
Perhaps these tasks allow the arms to reach the full table with a forward horizontal pose. From a left base near X = −0.3 m, placement into red at X ≈ +0.315 m would require about 0.6 m laterally, perhaps close to a 0.6 m maximum. Assigning the wooden toys to the right would avoid that placement reach, but downward grasps near X = −0.35 m, Y = −0.1 m, Z = 0.93 m would be about 0.65 m from a right base at X = +0.3 m and might be unreachable. A handoff is another possibility, though I would prefer to avoid it. Moving the red basket closer and returning it later is a fallback suggested by the skill, but is not an ideal way to meet the requested right-basket placement. I should first test whether a suitable placement orientation makes the left-arm reach possible.
The bases may not actually be at X = ±0.3 m. In the high view, the left base appears near X = −0.4 m, Y = −0.45 m, and the right near X = +0.4 m. If so, the left-to-red reach might be about 0.8 m and impossible without changing the placement geometry. The fingers can supply some lateral extension. During the intermediate rotations, their direction swings toward +X, adding about 0.05 m, while the fully horizontal initial orientation q0 points them along +Y and adds no X reach. A diagonal +X/+Y direction could add about 0.11 m laterally. Pointing the fingers along +X could add approximately 0.158 m: link6 at X = +0.16 m would put the fingertips near X = +0.318 m, requiring about 0.46 m from a base at X = −0.3 m. That may make red placement feasible.
I should therefore keep placement orientation flexible. Starting from q0, whose local X points along environment +Y, a −90-degree yaw about environment Z should point the fingers along +X. I tentatively calculate q_yaw = Rz(−90°) × q0 as [0.5, −0.5, 0.5, 0.5] in wxyz order: multiplying [0.707, 0, 0, −0.707] by [0.707, 0, 0, 0.707] gives that result. This resembles an earlier downward-orientation candidate, so I need to check its actual local-X direction rather than assume it points +X. I estimate this yaw change from q0 as 90 degrees, or 1.571 rad, requiring an intermediate pose. A −45-degree yaw may also provide enough reach. The camera’s resulting direction still needs checking, and I do not need to settle this until after grasping.
Before the next grasps, I should withdraw into open space, perhaps toward Z = 1.03 m and Y = −0.25 m. Choosing the central watch for the left arm would require reaching X ≈ +0.065 m, Y ≈ −0.1 m, Z = 0.93 m in the downward orientation, about 0.38 m across from its estimated base. That may be feasible, and the precheck can help assess it. The right could instead grasp the watch and place it into white with fingers pointing toward −X. For the wooden toys, a right-arm lion grasp at X ≈ −0.34 m would involve about 0.64 m laterally, compared with about 0.615 m for a left-arm red placement at X ≈ +0.315 m. Sideways fingers might make either route feasible. Splitting the toys between arms is another option: the right horse grasp at X ≈ −0.25 m would involve about 0.55 m, while the left lion would be easy to grasp but require about 0.62 m of crossing placement. A handoff remains possible but seems unnecessary for now.
I will proceed with the left lion to red and right central car to blue first, followed by the left horse to red and right central watch to white. If red remains unreachable for the left arm even with sideways placement, I can reconsider a right-arm handoff or basket movement. I think the planned approach is likely feasible, but it is not yet verified.
Both grippers are open over white and blue, nearly horizontal and around Z = 0.91 m. I can lift toward Z = 1.05 m while retreating toward Y = −0.18 m. I estimate the left displacement as −0.1 m in Y and +0.14 m in Z, with a norm of 0.172 m, and the right displacement as similar, about 0.17 m. I could hold their orientations during withdrawal, but downward grasps will require rotation. Using the current left quaternion [0.793, 0.008, 0.211, 0.572] and the downward quaternion [0.707, 0, 0.707, 0], I estimate a dot product of 0.56 + 0.149 = 0.709 and an orientation distance of 1.57 rad, above the 1 rad limit. For the right quaternion [0.773, −0.005, 0.144, 0.618], I estimate 0.546 + 0.102 = 0.648 and a distance of 1.73 rad. Both need intermediate rotations. I could use midpoint orientations, or consider the alternative downward quaternion [0, 0.707, 0, −0.707], which closes along Y but points the camera upward. My tentative dot-product calculation for that alternative is 0.149 − 0.404 = −0.255, with absolute value 0.255 and an orientation distance of 2.88 rad, so it does not help. Two or three rotation stages may again be necessary, though now I can combine intermediate rotations with approach motions because no objects are held.
A horizontal grasp from the front is another possibility. Keeping q0 with fingers along +Y, I could approach near Y = −0.3 m and grasp at Z ≈ 0.78 m, avoiding the downward rotation and simplifying placement. For the car and wooden toys, link6 at Z ≈ 0.80 m would let the fingers straddle the object while closing along environment X, since q0’s local Y points along −X. Closing across the car’s X-aligned length may be less suitable than across its width, but a 90-degree yaw could change the closing direction. The upright watch could be approached horizontally across its X width, and the lion or horse could be grasped across the body at Z ≈ 0.82 m. Horizontal fingers might contact the table if the pads extend too low; an estimated thickness of 0.02 m suggests Z = 0.80 m could be adequate, but I have not verified that.
For such a grasp, I would put link6 at the object’s center height and about 0.15 m behind it in Y, using the fingertip geometry for alignment. The wrist camera would look forward and downward. Grasping the car across its front and rear might still be stable. The horse would need a suitable narrow grasp region rather than an arbitrary closure across its base or head. I estimate the lion’s X width as 0.05 m and Y depth as 0.04 m, and the horse’s X width as 0.04 m with a possible Y depth of 0.08 m. The central car may have a diagonal X-oriented long axis, with length about 0.07 m and width about 0.04 m; a 45-degree yaw might better align the pads across its width. Nevertheless, the downward grasp has already worked and is the more reliable choice here.
With 937 steps remaining, an estimate of about 80 steps per object would total 320 steps for the four objects, leaving ample room. I will continue with downward grasps, using exact SLERP intermediates and 15-step motions where appropriate. I can move above the next targets while rotating through an intermediate orientation 55% of the way from each measured pose toward downward.
The lion’s grasp point still needs stereo refinement. Its round body may be near pixel (161, 248), with its head near (149, 241), though I am uncertain about which part is which. The initial crop may show it facing left with the large mane or head on the right. I can inspect a high-camera crop or move the wrist above it for a clearer view; the current left wrist mainly shows white. The central car can likewise be estimated from the high view and refined with the wrist camera.
Using a tentative grasp height of Z = 0.79 m, lion pixel (157, 247) may give X ≈ −0.340 m. Earlier, pixel (158, 246) at Z = 0.78 m gave approximately X = −0.339 m, Y = −0.12 m; at Z = 0.79 m I estimate X ≈ −0.332 m, Y ≈ −0.125 m. Horse pixel (199, 247) at Z = 0.79 m may give X ≈ −0.239 m, Y ≈ −0.125 m. Central-car pixel (256, 264) at Z = 0.78 m may give X ≈ −0.131 m, Y ≈ −0.161 m. Central-watch pixel (352, 242) at Z = 0.79 m may give X ≈ +0.062 m, Y ≈ −0.116 m. I will calculate the coordinates at the chosen heights. The table is likely at Z = 0.75 m, the car center around Z = 0.775 m, and the lion’s body top perhaps Z = 0.79 m with a grasp center at Z = 0.80 m. The horse’s body may also be at Z = 0.80 m. An approach link6 height of Z = 1.04 m should allow viewing and alignment above them.
The arms are currently near Y = −0.08 m, while the objects are around Y = −0.12 to −0.16 m, so the approaches are not far. The lion is approximately at X = −0.33 m, Y = −0.125 m and the central car at X = −0.13 m, Y = −0.16 m. The arms could approach side by side with about 0.2 m of separation. They are above the front rims, so I intend to move in negative Y toward the objects while lifting to Z = 1.05 m and rotating toward downward. Before commanding motion, I will calculate SLERP orientations at fractions 0.5 and 0.55 from each current measured orientation toward the downward pose, along with high-camera position estimates for the remaining objects.