小车估计中心现在更低,位于 z = 0.771米和 y = −0.064米,此前向前移动了约 0.012米。我估计其侧躺厚度为 0.042米。保险杠抓取没有保持住,所以我将尝试横跨其车身进行更深的抓取。连杆高度 z = 0.91米会使接触点位于手指方向约 0.139米处,指尖接近 z = 0.752米,靠近桌面,可能接触下边缘或轮子。
我需要理解侧躺几何。如果小车侧面朝上,其原始 X–Z 侧面平面现在水平:原始竖直 Z 方向沿世界 Y,原始 Y 宽度沿世界 Z。因此短的水平尺寸是其原始高度,约 0.04米,而非原始宽度约 0.05米。沿世界 Y 闭合会夹住车顶和底盘,跨越该原始高度。轮子在侧面凸出,但朝上的侧面本身不是对置接触面。深抓取可使夹垫抵住车顶和底盘,所需 0.04米开口完全在夹爪范围内。我估计质心在世界 z = 0.77米附近,闭合接触沿世界 Y 居中。在连杆 z = 0.91米时,指尖将刚好在假设桌面 z = 0.75米之上,夹垫跨度约 z = 0.75–0.81米。
原始尝试中小车是直立的吗?在观测 90 中,第一次掉落前,其估计中心在 z = 0.78米,腕部视图显示车顶、“53”标志和挡风玻璃。原始高机位相机视图也显示车顶,因此最初是直立的。90° 偏航抓取沿世界 Y 跨越其原始宽度闭合,指尖约在 z = 0.78米,夹垫接触侧身中部。我认为光滑车身和浅指尖接触使其滑脱并旋转到侧面。在连杆 z = 0.91米处更深抓取,指尖接近 z = 0.752米,应能更低地环绕车身和轮子。既然它已侧躺,跨越其原始高度夹取可能更稳定,因为车顶和底盘提供更平坦的对置表面。我将使用 90° 偏航并瞄准该更深连杆高度。
篮子间隙仍不确定。小车现在在 y = −0.064米,篮子前壁可能接近 y = −0.02米。张开手指偏移 0.045米时,后指将接近 y = −0.019米,可能仍碰到篮子。白色篮子前壁底部可能反而接近 y = −0.005米:其前部出现在图像行 210 附近,对应假设桌面高度 z = 0.75米时的 y = −0.005米。这样后指与壁之间约 0.014米,估计手指厚度 0.01米,因此可能安全。蓝色篮子前部类似。
我应该把小车再往前移吗?青椒在 y = −0.124米附近。小车中心在 y = −0.064米,水平宽度约 0.04米,其 Y 范围约 −0.084 到 −0.044米。向前移动 0.02米将变为 −0.104 到 −0.064米。青椒估计 Y 范围 −0.15 到 −0.10米,因此可能在 −0.104米附近接触。我也考虑过将小车向左推向 x = −0.18米以远离 x = −0.125米附近的青椒,但小车当前 X 范围 −0.196 到 −0.112米与青椒估计范围 −0.16 到 −0.10米重叠。我宁愿让小车留在原地。
稍微斜向的闭合方向可能减少后指朝篮子延伸的距离。在 80° 偏航时,局部 Y 在 260°,约 [−0.174, −0.985, 0],相反的后指方向为 [+0.174, +0.985, 0],在 Y 方向增加约 0.044米。几乎不变。在 100° 偏航时,闭合方向约 [+0.174, −0.985, 0],后指朝相反方向,X 分量为负指向白色篮子,似乎更糟。在 70° 偏航时,闭合方向约 [−0.342, −0.94, 0],后指在 Y 方向增加约 0.042米。在 45° 偏航时,后指方向分量为 [+0.707, +0.707, 0],在 Y 方向仅增加约 0.032米,但闭合轴与小车短尺寸成 45°。斜向抓取的投影长度可能约 0.07米,仍在开口内。在 60° 偏航时,后指在 Y 方向增加约 0.039米,X 方向增加 0.025米。这些变化似乎都不决定性。我倾向于 90° 偏航并小心下降,若受阻则停止。
右臂在放置巧克力后能回收小车吗?我最初想知道从另一侧以 −90° 偏航接近是否会使后指朝前而非朝篮子,但闭合轴无方向:手指仍占据相同的 ±Y 位置。倾斜接近可能使指体避开,但我需要区分闭合方向与手指延伸方向。
对于我一直使用的姿态,构造为 (ψ) × (−a) × (90°),其中 a 是向下倾斜,ψ 是绕世界 Z 的额外偏航。完全向下姿态使用 a = 90°。当 a = 60° 且 ψ = 90° 时,构造为 (90°) × (−60°) × (90°)。在额外偏航前,局部 X 指向 [0, 余弦(a), −正弦(a)]。偏航 ψ 后,它指向 [−正弦(ψ)余弦(a), 余弦(ψ)余弦(a), −正弦(a)]。因此,在 ψ = 90° 时,手指指向 [−余弦(a), 0, −正弦(a)]:朝向世界 −X 并向下,而非沿 Y 向前。偏航改变了接近方向以及闭合方向。
我想知道 ψ = 180° 是否能提供所需的前方接近,但要求 X 分量为零且 Y 分量为正余弦(a) 得到 ψ = 0°,即原始偏航零姿态,其局部 Y 沿世界 −X 闭合。当 ψ = 90° 且沿世界 Y 闭合时,倾斜手指从连杆向左延伸,因此连杆需在小车右侧。这可能使其靠近蓝色篮子,左臂将不得不横跨。
绕世界 Y 旋转同时保持局部 Y 沿世界 Y 不能解决此问题:它使局部 X 在 X–Z 平面内倾斜,因此其水平分量沿世界 X。水平接近垂直于闭合轴。因此沿 Y 闭合的倾斜接近将来自沿 X 的一侧,而非沿 Y 的前方。在 ψ = −90° 时,局部 X 将指向 [+余弦(a), 0, −正弦(a)],使连杆位于小车左侧。我想知道局部 Y 是否会变成 −Y;无论如何,它将是相同的无方向闭合轴。该侧靠近白色篮子。从右侧以 ψ = 90° 接近使连杆靠近蓝色篮子。垂直接近可能是两者之间的最佳选择。
使用双臂稳定并抬起小车是另一种可能,但技能要求除非必要否则避免。如果更深抓取有效,则不应必要。直接将小车推入蓝色篮子也不吸引人,因为篮子前壁约 0.06米高,因此不能简单推过而不抬起。我可以倾斜篮子或将容器移近,根据技能对远处可移动容器的指导,但此处似乎不必要,且可能干扰其他物体。用夹爪钩住轮子并抬起会更复杂。
我可以推迟小车,用左臂拾取青椒,让右臂完成巧克力然后拾取黄椒,将两辆小车留到以后。无需坚持立即回收。不过,右臂当前拿着 ’s 巧克力棒,空的左夹爪在掉落的小车上方。我现在将尝试改变策略:使用精确的新定位和横跨车身的更深抓取,而非重复保险杠抓取。
首先我需要打开左夹爪并在当前连杆高度 z = 1.016米处旋转至 90° 偏航,指尖约在 z = 0.858米,避开小车。90° 偏航四元数在顺序下约为 [0, −0.707, 0, 0.707]。从当前偏航零姿态旋转 90° 超过 1弧度命令限制,因此我需要先到中间 45° 偏航姿态。我考虑了一个 8 步移动,左连杆在 z = 1.03米且夹爪打开,同时将右连杆移至 (0.09, −0.1, 1.07) m 并仍持有巧克力。后续路点可将左连杆置于 (−0.154, −0.064, 1.0) m 并 90° 偏航,右连杆置于 (0.18, −0.05, 1.06) m。小步运输增量可能有助于避免之前的逆运动学失败。
对于立即动作,我将使用 6 步。右臂当前在 (−0.008, −0.188, 1.066) m;我估计移动到 (0.09, −0.1, 1.07) m 约 0.134米,因此可能通过预检查。左臂的中间 45° 旋转在姿态限制内。我将在 (−0.153, −0.056, 1.03) m 处重新打开左夹爪并使用 45° 偏航四元数,同时在向红色篮子递送期间保持右臂巧克力抓取及其姿态。
原文9,012 字
The car’s estimated center is now lower, at z = 0.771 m and y = −0.064 m, after moving forward about 0.012 m. I estimate its side-resting thickness at 0.042 m. The bumper grasp did not hold, so I’ll try a deeper grasp across its body. A link height of z = 0.91 m would put the contact point about 0.139 m along the fingers and the fingertips near z = 0.752 m, close to the table, where they might contact the lower edges or wheels.
I need to understand the side-resting geometry. If the car’s side face is upward, its original X–Z side plane is now horizontal: its original vertical Z direction lies along world Y, and its original Y width lies along world Z. The short horizontal dimension is therefore its original height, about 0.04 m, rather than its original width of about 0.05 m. Closing along world Y would pinch the roof and underbody across that original height. The wheels protrude on the side, but the upward-facing side itself would not be the opposing contact surface. A deep grasp could put the pads against the roof and underbody, with the required 0.04 m opening comfortably within the gripper’s range. I estimate the center of mass near world z = 0.77 m, with the closing contacts centered along world Y. At link z = 0.91 m, the fingertips would be just above the assumed table at z = 0.75 m, and the pads would span approximately z = 0.75–0.81 m.
Was the car upright during the original attempt? In observation 90, before the first drop, its estimated center was at z = 0.78 m, and the wrist view showed the roof, the “53” logo, and the windshield. The original high-camera view also showed the roof, so it was initially upright. The 90° yaw grasp closed along world Y across its original width, with the fingertips at about z = 0.78 m and the pads contacting the middle of the side body. I think the smooth body and shallow tip contact allowed it to slip and rotate onto its side. A deeper grasp at link z = 0.91 m, with fingertips near z = 0.752 m, should reach lower around the body and wheels. Now that it is on its side, pinching across its original height may be more stable because the roof and underbody offer flatter opposing surfaces. I’ll use 90° yaw and aim for that deeper link height.
Basket clearance is still uncertain. The car is now at y = −0.064 m, and the basket’s front wall may be near y = −0.02 m. With an open-finger offset of 0.045 m, the rear finger would be near y = −0.019 m and might still touch the basket. The white basket’s front-wall bottom may instead be near y = −0.005 m: its front appears around image row 210, which corresponds to y = −0.005 m at the assumed table height of z = 0.75 m. That would leave about 0.014 m between the rear finger and the wall, with an estimated finger thickness of 0.01 m, so it might be safe. The blue basket’s front is similar.
Should I move the car farther forward? The green pepper is near y = −0.124 m. With the car’s center at y = −0.064 m and its horizontal width around 0.04 m, its Y extents are approximately −0.084 to −0.044 m. Moving it forward by 0.02 m would change those extents to −0.104 to −0.064 m. The pepper’s estimated Y extents are −0.15 to −0.10 m, so they could touch near −0.104 m. I also considered pushing the car left toward x = −0.18 m to move it away from the pepper near x = −0.125 m, but the car’s current X extent of −0.196 to −0.112 m overlaps the pepper’s estimated extent of −0.16 to −0.10 m. I would rather leave the car where it is.
A slightly diagonal closing direction might reduce how far the rear finger extends toward the basket. At 80° yaw, local Y would be at 260°, approximately [−0.174, −0.985, 0], and the opposite rear-finger direction would be [+0.174, +0.985, 0], adding about 0.044 m in Y. That is nearly unchanged. At 100° yaw, the closing direction would be approximately [+0.174, −0.985, 0], putting the rear finger in the opposite direction with a negative X component toward the white basket, which seems worse. At 70° yaw, the closing direction would be approximately [−0.342, −0.94, 0], with the rear finger adding about 0.042 m in Y. At 45° yaw, the rear-finger direction would have components [+0.707, +0.707, 0], adding only about 0.032 m in Y, but the closing axis would be 45° from the car’s short dimension. A diagonal grasp might have a projected length of about 0.07 m, still within the opening. At 60° yaw, the rear finger would add about 0.039 m in Y and 0.025 m in X. None of these changes seems decisive. I favor 90° yaw with a careful descent, stopping if it is blocked.
Could the right arm recover the car after placing the chocolate? I initially wondered whether approaching from the other side with −90° yaw would put the rear finger toward the front rather than the basket, but the closing axis is undirected: the fingers would still occupy the same ±Y positions. A tilted approach might keep the finger bodies clear, though I need to distinguish the closing direction from the direction in which the fingers extend.
For the orientations I have been using, the construction is Rz(ψ) × Rx(−a) × Rz(90°), where a is the downward tilt and ψ is the additional yaw about world Z. The fully downward pose uses a = 90°. With a = 60° and ψ = 90°, the construction is Rz(90°) × Rx(−60°) × Rz(90°). Before the additional yaw, local X points along [0, cos(a), −sin(a)]. After yaw ψ, it points along [−sin(ψ)cos(a), cos(ψ)cos(a), −sin(a)]. Thus, at ψ = 90°, the fingers point along [−cos(a), 0, −sin(a)]: toward world −X and down, rather than forward along Y. The yaw changes the approach direction as well as the closing direction.
I wondered whether ψ = 180° would provide the desired front approach, but requiring a zero X component and a positive Y component of cos(a) gives ψ = 0°, the original yaw-zero orientation whose local Y closes along world −X. With ψ = 90° and closing along world Y, the tilted fingers extend leftward from the link, so the link would need to be to the right of the car. That could bring it near the blue basket, and the left arm would have to reach across.
Rotating about world Y while keeping local Y along world Y does not solve this: it tilts local X within the X–Z plane, so its horizontal component is along world X. The horizontal approach is perpendicular to the closing axis. A tilted approach closing along Y would therefore come from one side along X, not from the front along Y. At ψ = −90°, local X would point along [+cos(a), 0, −sin(a)], letting the link sit left of the car. I wondered whether local Y would then be −Y; in any case, it would be the same undirected closing axis. That side is near the white basket. Approaching from the right with ψ = 90° places the link near the blue basket. A vertical approach may be the best option between them.
Using both arms to stabilize and lift the car is another possibility, but the skill says to avoid that unless necessary. It should not be necessary if the deeper grasp works. Pushing the car directly into the blue basket is also unattractive because the basket’s front wall is about 0.06 m high, so I cannot simply push it over without lifting. I could tip the basket or move the container closer under the skill’s guidance for distant movable containers, but that seems unnecessary here and could disturb other objects. Hooking a wheel with the gripper and lifting would be more complicated.
I could postpone the car, use the left arm to pick the green pepper, and let the right finish the chocolate and then pick the yellow pepper, leaving both cars for later. There is no need to insist on immediate recovery. Still, the right arm is currently holding the Hershey’s bar and the empty left gripper is above the dropped car. I’ll try the changed strategy now: use the precise new localization and a deeper grasp across the body rather than repeating the bumper grasp.
First I need to open the left gripper and rotate toward 90° yaw at its current link height of z = 1.016 m, with fingertips around z = 0.858 m and clear of the car. The 90° yaw quaternion is approximately [0, −0.707, 0, 0.707] in wxyz order. The 90° rotation from the current yaw-zero pose exceeds the 1 rad command limit, so I need the intermediate 45° yaw pose first. I considered an 8-step move with the left link at z = 1.03 m and the gripper open, while moving the right link to (0.09, −0.1, 1.07) m with the chocolate still held. A subsequent waypoint could put the left link at (−0.154, −0.064, 1.0) m with 90° yaw and the right at (0.18, −0.05, 1.06) m. Small transport increments may help avoid the earlier IK failures.
For the immediate action, I’ll use 6 steps. The right arm is currently at (−0.008, −0.188, 1.066) m; I estimate the move to (0.09, −0.1, 1.07) m at about 0.134 m, so it may pass the precheck. The left arm’s intermediate 45° rotation is within the orientation limit. I’ll reopen the left gripper at (−0.153, −0.056, 1.03) m and use the 45° yaw quaternion, while preserving the right chocolate grasp and its orientation during delivery toward the red basket.