reasoning summary需要先获取传送带速度,在准备阶段进行第一次移动。传送带高度可能为 .75。物体头部是绿色木槌?绿色手柄摇铃。第一个物体。机械臂末端执行器当前水平 +Y,手指可达 y -.195,距离目标 .03 很远。需要移动接近 y +~.2 x .2 z .96 并向下旋转。也许准备右臂在 x .25 y -.02 z .98 向下到 .91?如果末端执行器为 .90,末端手指 z .75。稳定手柄轴大致为世界 Y,闭合方向为世界 X;向下姿态链接 +X 向下,+Y 闭合世界 X,局部 Z 负世界 Y 可得到正确结果。四元数 [0.5,-.5,.5,.5]?计算初始偏航90 俯仰90 的期望旋转矩阵列 [(0,0,-1),(-1,0,0),(0,1,0)]。初始 R 将局部Y 映射到 -世界X。俯仰局部将 +X 映射到局部-Z 世界-Z。q * = [.5,-.5,.5,.5]。好,增量旋转局部Y 并向上时向前平移 y。然后当匹配返回时再下降。不需要先抓取。等待物体经过多个其他物体。用初始 5 个动作获取速度。我们可以分四个阶段定向 /8 ~.393 每个。右末端执行器初始 [.30,-.35,.92] 到 [.30,-.28,.95]。q 偏航90 俯仰22.5 = [.69352,-.13795,.13795,.69352]。左侧保持。
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Need conveyor speed first movement during prepare. Belt height maybe .75. Object head green mallet? green handled rattle. First object x.45 y .07 z .78. Arm eef current horizontal +Y fingers reach y -.195, far from target .03. Need move approach y +~.2 x .2 z .96 and rotate down. Might prepare right arm at x .25 y -.02 z .98 down to .91? End finger z .75 if EEF .90. Stable handle axis roughly world Y, closure world X; down orientation link +X down, +Y closing world X, local Z negative worldY leads proper. quaternion [0.5,-.5,.5,.5]? Compute R desired columns [(0,0,-1),(-1,0,0),(0,1,0)] for initial yaw90 pitch90. initial R z90 maps localY -worldX. pitch localY90 maps +X to local-Z world-Z. q z90*y90 = [.5,-.5,.5,.5]. Good rotate incremental localY and translate y forward while up. Then descend later when match returns. Need not grab first. Wait object through multiple other objects. Get speed with initial 5 actions. We can orient in four stages pi/8 ~.393 each. Right eef initial [.30,-.35,.92] to [.30,-.28,.95]. q yaw90 pitch22.5 = [.69352,-.13795,.13795,.69352]. Left held.